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36m^2-8m-68=
We move all terms to the left:
36m^2-8m-68-()=0
We add all the numbers together, and all the variables
36m^2-8m=0
a = 36; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·36·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*36}=\frac{0}{72} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*36}=\frac{16}{72} =2/9 $
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